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The limmiting molar conductivites ^^ ^(@...

The limmiting molar conductivites `^^ ^(@)` for `NaCl_(2) ` Kbr and KCl are 126,152 and 150 S `cm^(2)` respectively the `^^ ^(@)` for NaBr is

A

`128Scm^(2)"mol"^(-1)`

B

`302Scm^(2)"mol"^(-1)`

C

`278S cm^(2)"mol"^(-1)`

D

`176Scm^(2)"mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`^^_(NaBr)^(@)=^^_(NaCl)^(@)+^^_(KBr)^(@)-^^_(KCl)^(@)`
`=126+152-150=128 S cm^(2)"mol"^(-1)`
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