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Calculate ^^overset(oo)HOAc using approp...


Calculate `^^overset(oo)HOAc` using appropriate molar conductances of the electrolytes listed above at infinite dilution in water at `25^(@)C`

A

390.7

B

217.5

C

517.2

D

552.7

Text Solution

Verified by Experts

The correct Answer is:
A
`^^_(HOAc)^(oo)=^^_(NaOAc)^(oo)+^^_(HCl)^(oo)-^^_(NaCl)^(oo)`
`=91.0+426.2-126.5=517.2-126.5`
`=390.7S cm^(2)"mol"^(-1)`
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{:("Electrolyte",^^.^(oo)(Scm^(2)mol^(-1))),(KCI,149.9),(KNO_(3),145.0),(HCI,426.2),(NaOAC,91.0),(NaCI,126.5):} Calculate ^^_(HOAc)^(oo) using appropriate moalr conductances of the electrolytes listed above at infinite dilution in H_(2)O at 25^(@)C

How does the molar conductance of an electrolyte vary with dilution ?

Assertion Molar conductance of an electrolyte increases with dilution Reason Ions move fast in dilute solutions.

At infinite dilution, when the dissociation of electrolyte is complete, each ion makes a definite contribution towards the molar conductance of electrolyte, irrespective of the nature of the other ion with which it is associated. the molar conductance of an electrolyte at infinite dilution can be expressed as the sum of the contributions from its individual ions. A_(x)B_(y) rarr xA^(y+)+yB^(x-) Lambda_(m)^(@)(A_(x)B_(y))=xlambda_(A^(y+))^(@)+ylambda_(B^(x-))^(@) where, x and y are the number of cations and anions respectively. The degree of ionisation 'alpha' of weak electrolyte can be calculated as : alpha=Lambda_(m)/Lambda_(m)^(@) The molar conductances at infinite dilution for electrolytes BA and CA are 140 and 120 ohm^(-1) cm^(2) mol^(-1) . If the molar conductance at infinite dilute dilution of BX is 198 ohm^(-1) cm^(2) mol^(-1) , then at infinite dilution, the molar conductance of CX is :

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