The equivalent conductances at infinite dilution of HCl and NaCl are 426.15 and 126.15 mho `cm^(2) g eq^(-1)` respectively. It can be said that the mobility of :

Options

A. `H^(+)` ions is much more than that of `Cl^(-)` ions
B. `Cl^(-)` ions is much more than that of `H^(+)` ions
C. `H^(+)` ions is much more than that of `Na^(+)` ions
D. `Na^(+)` ions is much more than that of `H^(+)` ions

Answer

C

Explanation

`^^_((aq))^(@)HClgtgtA^_(eq)^(@)(NaCl)`. Since `Cl^(-)` ions are common. This means their ionic conductance of `H^(+)gtgt` ionic conductance `prop` ionic mobility.
`lambda_("cation")propmu_("cation"),lambda_("anion")propmu_("anion")`
`therefore` H ions have much greater mobility than `Na^(+)` ion.