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Calculate Lambda(m)^(oo) for acetic acid...

Calculate `Lambda_(m)^(oo)` for acetic acid, given,
`Lambda_(m)^(oo)(HCl)=426 Omega^(-1)cm^(2)mol^(-1),Lambda_(m)^(oo)(NaCl)=126Omega^(-1)cm^(2)mol^(-1)`,
`Lambda_(m)^(oo)(CHCOONa)=91Omega^(-1)cm^(2)mol^(-1)`

A

481.5

B

390.5

C

299.5

D

516.9

Text Solution

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The correct Answer is:
B
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The equivalent conductances of sodium chloride, hydrochloric acid and sodium acetate at infinite dilution are 126.45, 426.16 and 91.0ohm^(-1) cm^(-1)"equiv"^(-1) , respectively, at 25^(@)C . Calculate the equivalent conducatance of acetic acid at infinite dilution. Lambda_(m)^(0)(HCl)="426.16 S cm"^(2)mol^(-1) Lambda_(m)^(0)(NaCl)="126.45 S cm"^(2)mol^(-1) Lambda_(m)^(0)(CH_(3)COONa)="91 S cm"^(2)mol^(-1)

Calculte molar conductance at infinite dilution for acetic acid, given A_(m)^(oo)HCI=425 ohm^(-1)cm^(-1),A_(m)^(oo)NaCI=188 ohm^(-1)cm^(-1),A_(m)^(oo)CH_(3)COOHNa=96 ohm^(-1)cm^(-2)mol^(-1)

Calculate the degree of dissociation of 0.02 M acetic acid at 298K, given that lambda_(CH_(3)COOH)=11.7ohm^(-1)cm^(2)"mol"^(-1) lambda_((CH_(3)COO^(-)))=40.9ohm^(-1)cm^(2)"mol"^(-1) lambda(H^(+))^(@)=349.1ohm^(-1)cm^(2)"mol"^(-1)

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Calculate degree of dissociation of 0.02 M acetic acid at 298 K given that mho_(m)(CH_(3)COOH)=17.37 cm^(2) mol^(-1),lambda_(m)^(@)(H+)=345.8 S cm^(2) mol^(-1), lambda_(m)^(@)(CH_(3)COO^(-))=40.2 Scm^(2) mol^(-1)

State Kohlrausch law of independent migration of ions. Write an expression for the molar conductivity of acetic acid at infinite dilution according to Kohlrausch law. {:((b),"Calculate",:,wedge^(@)m" for acetic acid."),(,"Given that",:,wedge^(@)m(HCl)=426 " S " "cm"^(2)mol^(-1)),(,,,wedge^(@) m(NaCl)=126 " S " cm^(2) mol^(-1)),(,,,wedge^(@) m(CH_(3)COONa)=91 " S " cm^(2)mol^(-1)):}

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