A current is passed through two cells connected in series. The first cell contain `x(NO_(3))_(2)` (aq) and the second cell contains `y(NO_(3))_(2)(aq)` . The relative atomic masses of x and y are in the ratio of x to that of y?

Options

A. `3:2`
B. ` 1:2`
C. `1:3`
D. ` 3:1`

Answer

C

Explanation

If atomic mass of x=a, then that of y=2a
`therefore` Eq. mass `=("at. Mass")/("valency")`
`therefore` Eq. mass of `x=a//3`. Eq mass of
`y=2a//2=a`.
`("Mass of x")/("Mass of y")=("Eq. mass of x")/("E q mass of y")`
`=(a//3)/(1)=(1)/(3)= 1:3`