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The limiting molar conductivities of HCl...

The limiting molar conductivities of HCl, `CH_(3)COONa` and NaCl are respectiley 425, 90 and 125 mho `cm^(2) " mol"^(-1)` and `25^(@)C`. The molar conductivity of 0.1M `CH_(3)COCH` solution is 7.8 mho `cm^(2) "mol"^(+1)` at the same temperature is

A

0.1

B

0.02

C

0.15

D

0.03

Text Solution

Verified by Experts

The correct Answer is:
B
`^^_(CH_(3)COOH)^(@)=^^_(CH_(3)COONa)^(@)+^^_(HCl)^(@)-^^_(NaCl)^(@)`
`=90+425-125=390 mho cm^(2)"mol"^(-1)`
`a=(^^_(m)^(@))/(^^_(m)^(@))=(7.8)/(390)=0.02`
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