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Daniel cell, the EMF of the cell can b e...

Daniel cell, the EMF of the cell can b e increased b y

A

increasing the concentration of `Zn^(2+)` ions

B

increasing the concentration of `Cu^(2+)` ions

C

increasing the concentration of `Cu^(2+)` ions

D

decreasing the concentration of `Zn^(2+)` ions.

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To solve the question regarding how to increase the EMF (Electromotive Force) of a Daniel cell, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Daniel Cell:** The Daniel cell consists of two half-cells: one with zinc (anode) and one with copper (cathode). The overall reaction involves the oxidation of zinc and the reduction of copper ions. 2. **Know the Nernst Equation:** The EMF of the cell can be calculated using the Nernst equation: \[ E_{\text{cell}} = E^\circ_{\text{cell}} - \frac{0.0591}{n} \log \left(\frac{[\text{Zn}^{2+}]}{[\text{Cu}^{2+}]}\right) \] where \(E^\circ_{\text{cell}}\) is the standard EMF, \(n\) is the number of moles of electrons transferred, and \([\text{Zn}^{2+}]\) and \([\text{Cu}^{2+}]\) are the concentrations of zinc and copper ions, respectively. 3. **Identify the Factors Affecting EMF:** To increase the EMF (\(E_{\text{cell}}\)), we need to manipulate the terms in the Nernst equation. Specifically, we want to decrease the value of the logarithmic term. 4. **Manipulate Concentrations:** The logarithmic term is: \[ \log \left(\frac{[\text{Zn}^{2+}]}{[\text{Cu}^{2+}]}\right) \] To decrease this term, we can either: - Decrease the concentration of zinc ions \([\text{Zn}^{2+}]\) - Increase the concentration of copper ions \([\text{Cu}^{2+}]\) 5. **Conclusion:** Therefore, to increase the EMF of the Daniel cell, we can: - Decrease the concentration of zinc ions (Option D) - Increase the concentration of copper ions (Option B) Thus, the correct options to increase the EMF of the Daniel cell are **Option B (Increase concentration of Cu) and Option D (Decrease concentration of Zn)**.

To solve the question regarding how to increase the EMF (Electromotive Force) of a Daniel cell, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Daniel Cell:** The Daniel cell consists of two half-cells: one with zinc (anode) and one with copper (cathode). The overall reaction involves the oxidation of zinc and the reduction of copper ions. 2. **Know the Nernst Equation:** ...
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