The products formed when an aqueous solution of `NaBr` is electrolysed in a cell having inert electrodes are `:`

Options

A. Na and `Br_(2)`
B. Na and `O_(2)`
C. `H_(2),Br_(2)` and NaOH
D. `H_(2)` and `O_(2)`

Answer

C

Explanation

`NaBr(aq)hArrNa^(+)(aq)+Br^(-)(aq)`
`Na^(+)+e^(-)rarrNa`
`2H_(2)O+ 2e^(-)rarrH_(2)=2OH^(-)`
As R.P. of 2nd reactions is more `H_(2)` is produced at cathode
`2Br^(-)rarrBr_(2)+2e^(-)`
`2H_(2)OrarrO_(2)+4 H^(+)+4e^(-)`
As O.P. of 1st reaction is more, `Br_(2)` is produced at anode `Na^(+)` from ionisation of NaBr and `OH^(-)` ions produced due to reduction of water at cathode combine to give NaOH.