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Calculate the equilibrium constant for t...

Calculate the equilibrium constant for the reaction `Cu(s)+2Ag^(+)(aq)rarrCu^(2+)(aq)+2Ag(s), E_(cell)^(@)=0.46 V`.

A

`4xx10^(15)`

B

`2.4xx10^(10)`

C

`2.0xx10^(10)`

D

`4xx10^(10)`

Text Solution

Verified by Experts

The correct Answer is:
A
`E_("cell")^(@) =( 0.0591)/(n)"log"k`
`"log" k=(0.46xx2)/(0.0591)= 15.566 8`
K=antilog 15.566 8=`10^(15)`
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