The cell , `Zn | Zn^(2+) (1M) || Cu^(2+) (1M) Cu (E_("cell")^@ = 1. 10 V)`,
Was allowed to be completely discharfed at `298 K `. The relative concentration of `2+` to `Cu^(2+) [(Zn^(2=))/(Cu^(2+))]` is :

Options

A. `9.65xx10^(4)`
B. antilog 24.08
C. 37.3
D. `10^(37.3)`

Answer

D

Explanation

The cell reaction is
`Zn+Cu^(2+)rarrZn^(2+)+Cu`
When the cell is completely discharged.
`E_("cell")=0`
Hence
` E_("cell")^(@)=(0.059)/( 2)"log"( [Zn^(2+)])/([Cu^(2+)])`
` 1.10=(0.0591)/(2)"log"([Zn^(2+)])/([C u^(2+)])`
or log `([Zn^(2+)])/(Cu^(2+)]=37.3`
or `([Zn^(2+)])/([Cu^(2+)])= 10^(37.3)`