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The electrode potentials for Cu^(2+)+e...

The electrode potentials for
`Cu^(2+)+e^(-)toCu^(+)` and
`Cu^(+)e^(-)toCu_(s)`
are `+0.15`V and `+0.50V` respectively the value of `E_((Cu^(2+))/(Cu))^(@)` will be?

A

0.650V

B

0.150V

C

0.500V

D

0.325V

Text Solution

Verified by Experts

The correct Answer is:
D
`Cu^(2+)(aq)+ e^(-)rarrCu^(+)(aq):E_(1)^(@)=0.15V`
`DeltaG_(1)^(@)=-nE_(2)^(@)F=-0.15F`
`Cu^(+)(aq)+e^(-)rarrCu(s):E_(2)^(@)=0.50V`
`DeltaG_(2)^(@)=-nE_(2)^(@)F=-0.50F`
`Cu^(2+)(aq)+2e^(-)rarrCu(s):E_(3)^(@)= ?`
`DeltaG_(3)^(@)=-nE_(3)^(@)F= -2E_(3)^(@)F`
`DeltaG_(3)^(@)=DeltaG_(1)^(@)+DeltaG_(2)^(@)`
`-2E_(3)^(@)F=-0.15F=0.50F`
`therefore E_(3)^(@)=(0.65)/(2)=0.325V`
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