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If n(2) moles of non-volatile solute are...

If `n_(2)` moles of non-volatile solute are dissolved in `n_(1)` moles of the solvent, Raoult's law is expressed mathematically as

A

`(p^(@)-p_(s))/(p^(@)) =(n_(2))/(n_(1)+n_(2))`

B

`(p^(@)-p_(s))/(p^(@))=(n_(1))/(n_(1)+n_(2))`

C

`(p^(@)-p_(s))/(p_(s)) =(n_(2))/(n_(1)+n_(2))`

D

`(p^(@)-p_(s))/(p_(s)) =(n_(1))/(n_(1)+n_(2))`

Text Solution

Verified by Experts

The correct Answer is:
A
`(p^(@)-p_(s))/(p^(@)) = x_(2) = (n_(2))/(n_(1)+n_(2))`
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