Home
Class 12
CHEMISTRY
The vapour pressure of a pure liquid A i...

The vapour pressure of a pure liquid A is 70 torr at 300K. It forms an ideal solution with another liquid B. The mole fration of B in the solution is 0.2 and total pressure of solution is 84 torr at 300K. The vapour pressure of pure liquid B at `26^(@)C` is

A

0.14 torr

B

560 torr

C

140 torr

D

70 torr

Text Solution

Verified by Experts

The correct Answer is:
C
`84 = 0.2x +0.8 xx 70 ( :' P = p_(A)^(@) x_(A) + p_(B)^(@) x_(B))`
or `x = (84 - 56)/(0.20) = 140` torr.
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    DINESH PUBLICATION|Exercise REVISION QUESTION|186 Videos

  • SOLUTIONS

    DINESH PUBLICATION|Exercise OBJECTIVE TYPE MCQs|47 Videos

  • SOLID STATE

    DINESH PUBLICATION|Exercise Brain storming|10 Videos

  • SOME BASIC CONCEPTS OF CHEMISTRY

    DINESH PUBLICATION|Exercise ULTIMATE PREPARATORY PACKAGE|20 Videos

Similar Questions

Explore conceptually related problems

The vapour pressure of a pure liquid A is 60 torr at 300K. It forms an ideal solution with another liquid B. The mole fraction of B is 0.25 and the total pressure of the solution is 82.5 torr at 300K. The vapour pressure of pure liquid B at 300K is

The vapour pressure of a pure liquid 'A' is 70 torr at 27^(@)C . It forms an ideal solution with another liquid B. The mole fraction of B is 0.2 and total pressure of the solution is 84 torr at 27^(@)C . The vapour pressure of pure liquid B at 27^(@)C is :

Vapour pressure of pure A is 70 mm of Hg at 25^(@)C . If it forms an ideal solution with B in which mole fraction of A is 0.8 and vapour pressure of the solution is 84 mm of Hg at 25^(@)C , then the vapour pressure of pure B at 25^(@)C is

The vapour pressure of a pure liquid A is 40 mm Hg at 310 K . The vapour pressure of this liquid in a solution with liquid B is 32 mm Hg . The mole fraction of A in the solution, if it obeys Raoult's law, is:

The vapour pressure of a pure liquid A is 40 mm Hg at 310 K . The vapour pressure of this liquid in a solution with liquid B is 32 mm Hg . Mole fraction of A in the solution , if it obeys Raoult's law is :

The vapour pressure of a pure liquid is 0.80 atm. When a non-volatile solute is added to this liquid, its vapour pressure drops to 0.60 atm. The mole fraction of the solute in the solution is

The vapour pressure of a pure liquid at 25^(@)C is 100 mm Hg. Calculate the relative lowering of vapour pressure if the mole fraction of solvent in solution is 0.8.