1g mole of oxalic acid is dissolved in 2 litre of solution. The concentration of solution is

Options

A. 0.5N
B. 2.0N
C. 2.5N
D. 1.0N

Explanation

To find the concentration of a solution in terms of molarity and normality, we can follow these steps:

### Step 1: Determine the number of moles of oxalic acid
Given that 1 gram mole of oxalic acid is used, we know that:
- 1 mole of oxalic acid = 1 gram mole.

### Step 2: Calculate the molarity of the solution
Molarity (M) is defined as the number of moles of solute per liter of solution. The formula for molarity is:
\[ \text{Molarity (M)} = \frac{\text{Number of moles of solute}}{\text{Volume of solution in liters}} \]

Here, we have:
- Number of moles of oxalic acid = 1 mole
- Volume of solution = 2 liters

Substituting these values into the formula:
\[ \text{Molarity} = \frac{1 \text{ mole}}{2 \text{ liters}} = 0.5 \text{ M} \]

### Step 3: Calculate the normality of the solution
Normality (N) is defined as the number of equivalents of solute per liter of solution. For acids, the number of equivalents is determined by the number of replaceable hydrogen ions (n-factor).

For oxalic acid (H₂C₂O₄), it has 2 replaceable hydrogen ions. Therefore, the n-factor is 2.

Using the relationship:
\[ \text{Normality (N)} = \text{Molarity (M)} \times n \text{-factor} \]

Substituting the values:
\[ \text{Normality} = 0.5 \text{ M} \times 2 = 1 \text{ N} \]

### Final Answers:
- Molarity of the solution = 0.5 M
- Normality of the solution = 1 N