Home
Class 12
CHEMISTRY
The molality of a soluton having 18 g of...

The molality of a soluton having 18 g of glucose (Molar mass=180) dissolved in 500 g of water is :

A

1.2m

B

0.4m

C

0.1m

D

0.2m

Text Solution

Verified by Experts

The correct Answer is:
D
`m = (18 xx 1000)/(180 xx 500) = 0.2m`
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    DINESH PUBLICATION|Exercise REVISION QUESTION|186 Videos

  • SOLUTIONS

    DINESH PUBLICATION|Exercise OBJECTIVE TYPE MCQs|47 Videos

  • SOLID STATE

    DINESH PUBLICATION|Exercise Brain storming|10 Videos

  • SOME BASIC CONCEPTS OF CHEMISTRY

    DINESH PUBLICATION|Exercise ULTIMATE PREPARATORY PACKAGE|20 Videos

Similar Questions

Explore conceptually related problems

What will be the molality of solution having 18 g of glucose ( molecular weight = 180 ) dissolved in 500 g of water ?

The molality of solution containing 15.20 g of urea ( molar mass = 60 ) dissolved in 150 g of water is ______.

The molarity of solution containing 15.20 g of urea, (molar mass = 60) dissolved in 150 g of water is

What is the molality of a solution in which 18 g of glucose (mol. wt. = 180) is dissolved in 500g of H_2O ?

The molarity of a solution having 18g of glucose dissolved in 500 g of water is

Calculate the freezing point of a solution containing 60 g glucose (Molar mass = 180 g mol^(-1) ) in 250 g of water . ( K_(f) of water = 1.86 K kg mol^(-1) )