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The number of iodine atoms present in 40...

The number of iodine atoms present in `40` mL solution of its `0.1` M solution is

A

`4.81 xx 10^(21)`

B

`24.08 xx 10^(21)`

C

`0.408 xx 10^(23)`

D

`6.02 xx 10^(22)`

Text Solution

Verified by Experts

The correct Answer is:
A
Iodine atoms `= 2 xx N xx (40 xx 10^(-3) xx 0.1)`
`= 2xx 6.02 xx 10^(23) x 40 xx 10^(4)`
`= 4.81 xx 10^(21)`
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