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0.2 moles of HCI and 0.1 moles of calciu...

0.2 moles of HCI and 0.1 moles of calcium chloride were dissolved in water to have 500mL of solution, the molarity of `CI^(-)` ions is

A

`0.04M`

B

`0.8M`

C

`0.4M`

D

`0.08M`

Text Solution

Verified by Experts

The correct Answer is:
B
`0.2` moles of `HCI` gives `CI^(-)` ions `= 0.2` moles 0.1 moles of `CaCI_(2)` gives `CI^(-)` ions `= 0.2` moles
Total moles of `CI^(-)` ions in `500 mL = 0.4` Molarity of `CI^(-)` ions = 0.8M
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