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10 gram of solute with molecular mass 10...

10 gram of solute with molecular mass 100 gram `mol^(-1)` is dissolved in 100 gram solvent to show `0.3^(@)C` elevation in boiling point. The value of molal elevation constant will be:

A

10

B

3

C

0.3

D

unpredictable

Text Solution

Verified by Experts

The correct Answer is:
C
`Delta T_(b) = K_(b) (W_(B))/(M_(B)).(1000)/(W_(A)), K_(b) = (DeltaT_(b).M_(B).W_(A))/(W_(B).1000)`
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