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The vapour pressure of water is 12.3kPa ...

The vapour pressure of water is `12.3kPa` at 300 K. The V.P. of 1M solution of a non-volatile non electrolyte solution is

A

`10.08 kPa`

B

`12.08 kPa`

C

`8.3kPa`

D

`10.3kPa`

Text Solution

Verified by Experts

The correct Answer is:
B
As the solution is quite dilute `1M ~~ 1m`. Thus, 1 mol of solute is present in `100g (55.5mol)` of water
`(1)/(1+55.5) = (12.3-p_(A))/(12.3)`
`p_(A) = 12.08 k Pa`
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