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A mixture contains 1 mole of volatile li...

A mixture contains 1 mole of volatile liquid A`(P_(A)^(@)`=100mm Hg) and 3 moles of volatile liquid B `(P_(B)^(@)`=80 mm Hg). If solution behaves ideally, the total vapour pressure of the distillate is :

A

85 mm Hg

B

86 mm Hg

C

90 mm Hg

D

92 mm Hg

Text Solution

Verified by Experts

The correct Answer is:
B
`p_(A) = p_(A)^(@) x_(A) = 100 xx (1)/(4) = 25 mm Hg`
`p_(B) = p_(B)^(@) x_(B) = 80 xx (3)/(4) = 60 mm Hg`
Mole fraction of A in vapour
`x'_(A) = (p_(A))/(p_(A)+p_(B)) = (25)/(85)`
Mole fraction of B in vapour
`x'_(B) = 1 - (25)/(85) = (60)/(85)`
V.P of distillate
`=x'_(A) p_(A)^(@) +x'_(B) p_(B)^(@)`
`= (25)/(85) xx 100 +(60)/(85) xx 80`
`= (1)/(85) (2500+4800) = (7300)/(85) = 85.88`
`~~ 86 mm Hg`
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