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Vapour pressure of pure water is 40 mm. ...

Vapour pressure of pure water is 40 mm. if a non-volatile solute is added to it, vapour pressure falls by 4 mm. Hence, molarity of solution is

A

6.17m

B

3.09m

C

1.54m

D

0.77m

Text Solution

Verified by Experts

The correct Answer is:
A
`(Deltap)/(p^(@)) = x_(B)`
`x_(B) = (4)/(40) = 0.1`
Thus, solution contains 0.1 mol of solute in 0.9 mol of water
Mass of water `= 0.9 xx 18 = 16.2 g`
Molarity of solution `= (0.1)/(16.2) xx 1000`
`=(100)/(16.2) = 6.17m`
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