`pH` of a `0.1 M` monobasic acid is found to be `2`. Hence, its osmotic pressure at a given temperature T K is

Options

A. `1.1RT`
B. `0.1RT`
C. `0.11RT`
D. `0.01RT`

Answer

C

Explanation

`pH = 3`
`pH = 2`
`:.[H^(+)] = 10^(-2)`
`C alpha = 10^(-2)`
`alpha = (10^(-2))/(10^(-1)) = 10^(-1)`
`i=1+alpha`
`i=1 +0.1 = 1.1`
`pi V = inRT`
`pi =i((n)/(V))RT`
`= 1.1 xx 0.1 xx RT = 0.11 RT`