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It potassium ferrocyanide is 75% ionized...

It potassium ferrocyanide is 75% ionized in the solution, its van't Hofff factor is.....

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The correct Answer is:
`rarr 4`
`{:(K_(4)[Fe(CN)_(6)],rarr,K_(4)^(+)+,Fe(CN)_(6)^(4-)),(1mol,,0,0),(1-alpha,,4alpha,4alpha):}`
Total `= 1 +4 alpha`
`i=(1+4alpha)/(1) = 1 +4alpha = 1 +4 xx 0.75`
`= 1+3 = 4`
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