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An engine operating between 100^(@)C and...

An engine operating between `100^(@)C` and `0^(@)C` takes `453.6 kcal` of heat. How much useful work can be done by it ?

A

`508.8 kJ`

B

`453.6 kcal`

C

`508.8 kcal`

D

None

Text Solution

Verified by Experts

The correct Answer is:
A
`T_(2)=100+273=373 K` and
`T_(1)=0+273=273 K`
`Q=453.6 kcal=453.6xx4.184`
`=1897.86 kJ`
Now, `(W)/(Q)=(T_(2)-T_(1))/(T_(2))`
W=1897.86 ((373-273)/(373))`
`W=508.8 kJ`
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