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One moles of anhydrous AB dissolves in w...

One moles of anhydrous `AB` dissolves in water and liberates `21.0 J mol^(-1)` of heat. The valueof `DeltaH^(Theta)` (hydration) of `AB` is `-29.4 J mol^(-1)`. The heat of dissolution of hydrated salt `AB.2H_(2)O(s)` is

A

`50.4 J mol^(-1)`

B

`8.4 J mol^(-1)`

C

`-50.4 J mol^(-1)`

D

`-8.4 J mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaH_(sol)` (anhyd. Salt)
`=[DeltaH_(sol)("hydrated salt") + DeltaH_("hydration")]`
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