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For hypothetical reversible reaction 1...

For hypothetical reversible reaction
`1//2A_(2)(g) +3//2B_(2)(g) rarr AB_(3)(g), DeltaH =- 20 kJ `if standard entropies of `A_(2),B_(2)`, and `AB_(3)` are `60,40` and `50JK^(-1) mol^(-1)` respectively. The above reaction will be equilibrium at

A

`400 K`

B

`500K`

C

`250K`

D

`200K`

Text Solution

Verified by Experts

The correct Answer is:
B
At equilibrium, `DeltaH=T DeltaS`
`T=(DeltaH)/(DeltaS)=(-20xx10^(3)J)/((50-3//2xx40-1//2xx60))`
`:. T= 500 K`
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