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An ideal gas expands from 10^(-3) m^(3) ...

An ideal gas expands from `10^(-3) m^(3)` to `10^(-2) m^(3)` at 300 K against a constant pressure of `10^(5) Nm^(-2)`. The workdone is

A

`-0.9 kJ`

B

`-900 kJ`

C

`270 kJ`

D

`-270 kJ`

Text Solution

Verified by Experts

The correct Answer is:
A
`W=-PDeltaV`
`P=10^(5)Nm^(-2)=1"atm"`,
`DeltaV=10-1=9 "Litres"[1m^(3)=10^(3)L]`
`W=-(1xx9xx101)/(1000)[1 L-"atom"=101 J]`
`=0.9 kJ`
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