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The equilibrium constant for certain rea...

The equilibrium constant for certain reaction is `100`. If the value `R` is given to be `2 cal K^(-1) mol^(-1)`, then standard Gibb's free energy change will be

A

`-2.764 kcal`

B

`2.674 kcal`

C

`2.764 kcal`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
D
`DeltaG^(@)=-2.303 RT log K`
`=-2.303xx2xx298xxlog100`
`=-2.303xx2xx298xx2`
`=-2745.2cal=-2.745 kcal`
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DINESH PUBLICATION-CHEMICAL THERMODYNAMICS AND CHEMICAL ENERGETICS -Exercise
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