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For a reaction Br(2)(l)+Cl(2)(g)to2BrC...

For a reaction
`Br_(2)(l)+Cl_(2)(g)to2BrCl` at `300K` the value of `DeltaH=7kcal` and `DeltaS` is `25 cal K^(-1)`. The free energy change is

A

`-500 cal`

B

`7493 cal`

C

`18 kJ`

D

`150 kcal`

Text Solution

Verified by Experts

The correct Answer is:
A

Apply `DeltaG=DeltaH-T DeltaS`
`=7000 cal-300xx25=-500cal`
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DINESH PUBLICATION-CHEMICAL THERMODYNAMICS AND CHEMICAL ENERGETICS -Exercise
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