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At what temperature, DeltaG of a reactio...

At what temperature, `DeltaG` of a reaction is equal to `-5.2 kJ mol^(-1)` ? `DeltaH` and `DeltaS` of the reaction are respectively `145.6 kJ mol^(-1)` and `116 JK^(-1)`.

A

`1300^(@)C`

B

`130 K`

C

`1300 K`

D

`130^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
C
`DeltaG=DeltaH-TDeltaS`
or `T=(DeltaH-DeltaG)/(DeltaS)=(145600(J)-5200(J))/(116(J))`
`=(150800)/(116)=1300K`
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