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The enthalpy of the reaction : H(2)O(2...

The enthalpy of the reaction :
`H_(2)O_(2)(l)toH_(2)O(l)+(1)/(2)O_(2)(g)` is `-23.5 kcal mol^(-1)` and the enthalpy of formation of `H_(2)O(l)` is `-68.3 kcal mol^(-1)`. The enthalpy of formation of `H_(2)O_(2)(l)` is

A

`-44.8 kcal mol^(-1)`

B

`44.8 kcal mol^(-1)`

C

`-91.8 kcal mol^(-1)`

D

`91.8 kcal mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`H_(2)+O_(2)toH_(2)O_(2)` is `DeltaH_(f)` of `H_(2)O_(2)`.
To get `H_(f)` for this reaction subtract equation `(i)` from `DeltaH_(f)` of `H_(2)O`.
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  10. The enthalpy change at 298 K of the reaction H(2)O(2)(l)toH(2)O(l)+1...

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