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The entropy change for the fusion of 1 m...

The entropy change for the fusion of `1 mol` of a solid which melts at `27^(@)C` is (latent heat of fusion `=600 kcal mol^(-1)`)

A

`2 cal deg^(-1)`

B

`22.2 cal deg^(-1)`

C

`180 kcal deg`

D

`0.5 cal^(-1)deg`

Text Solution

Verified by Experts

The correct Answer is:
A
`DeltaS_(fus)=(DeltaH_(fus))/(T)=(600)/(300)=2 cal deg^(-1)`
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