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DeltaG for a reaction at 300 K is -16 kc...

`DeltaG` for a reaction at `300 K` is `-16 kcal` and `DeltaH` is `-10 kcal`. The entropy of the reaction is

A

`20 cal deg^(-1)`

B

`86.6 cal deg^(-1)`

C

`166 cal deg^(-1)`

D

`100 cal deg^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`DeltaG=DeltaH-TDeltaS`
or `DeltaS=(DeltaH-DeltaG)/(T)=(-10-(-16))/(300)`
`=(6xx1000)/(300)=20cal deg^(-1)`
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