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Calculate the work done when 1.0 mol of ...

Calculate the work done when `1.0` mol of water at `373K` vaporises against an atmosheric pressure of `1.0atm`. Assume ideal gas behaviour.

A

`-6200 J`

B

`-306 J`

C

`-3100 J`

D

`-1550 J`

Text Solution

Verified by Experts

The correct Answer is:
C
Volume of `1` mol of water at `373 K`, `1` atm `(V_(1))=18cm^(3)=0.018 L`
Volume of `1` mol of water in vapour state at
`373 K`, `1 "atm"=(RT)/(P)`
`=(0.0821xx373)/(1)=30.62 L`
Now `w=-P(V_(2)-V_(1))`
`=1(30.62-0.018)`
`=-30.6 L-"atm"`
`=-30.6xx101.3=-3100 J`
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