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If the enthalpy of vaporisation of water...

If the enthalpy of vaporisation of water is `186.5 J mol^(-1)`, then entropy of its vaporisation will be

A

`0.5 JK^(-1) mol^(-1)`

B

`1.0 JK^(-1) mol^(-1)`

C

`1.5 JK^(-1) mol^(-1)`

D

`2.0 JK^(-1) mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A

`DeltsS=(DeltaH_(vap))/(T_(bp))=(186.5)/(373)=0.5JK^(-1)mol^(-1)`
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DINESH PUBLICATION-CHEMICAL THERMODYNAMICS AND CHEMICAL ENERGETICS -Exercise
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  13. The free energy change DeltaG = 0, when

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