The heat of neutrasation of a strong acid and a strong alkali is `57.0KJ mol^(-1)` . The heat released when `0.5` mole of `HNO_(3)` solution is mixed with `0.2` mole of `KOH` is

Options

A. `57.0 kJ`
B. `11.40 kJ`
C. `28.5 kJ`
D. `34.9 kJ`

Answer

B

Explanation

Here, `0.2` moles of `NaOH` is limiting reagent. Therefore, amount of heat liberated by neutralisation of `0.20` moles of `NaOH` is `=5.70xx0.2=11.4kJ`.