A particular reaction has a negative value for the free energy change. Then at ordinary temperature

Options

A. It has a large `-ve` value for the entropy change
B. It has a large `+ve` value for the entropy change
C. It has small `+ve` value for enthalpy change
D. It has a `+ve` value for the entropy change and a `-ve` value for the enthalpy change

Answer

D

Explanation

The reaction is spontaneous `(DeltaG=-ve)`. Thus, at ordinary temperature
`DeltaS=+ve`, `DeltaH=-ve`.