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The bond dissociation energy of gaseous ...

The bond dissociation energy of gaseous `H_(2),Cl_(2)` and `HCl` are `104,58` and `103 kcal mol^(-1)` respecitvely. Calculate the enthalpy of formation for `HCl` gas.

A

`-44kcal`

B

`-88 kcal`

C

`-22 kcal`

D

`-11 kcal`

Text Solution

Verified by Experts

The correct Answer is:
C
The required equation is
`(1)/(2)H_(2)(g)+(1)/(2)Cl_(2)(g)toHCl(g)`, `DeltaH_(f)=?`
`DeltaH_(f)=sum B.E. "of reactants"-sum B.E."of products`.
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