The heat of combustion of graphite and carbon monoxide respectively are `393.5 kJ mol^(-1)` and `283 kJ mol^(-1)`. Thus, heat of formation of carbon monoxide in `kJ mol^(-1)` is

Options

A. `+172.5`
B. `-110.5`
C. `-10760`
D. `-676.5`

Answer

B

Explanation

`DeltaH_(f)(CO)=[DeltaH_(comb)"of"C]-[DeltaH_(comb)"of"CO]`
`=-393.5-(-283)=-110.5 kJ mol^(-1)`