An endotthermic reaction is non-spontaneous at freezing point of water and becomes feasible at its boiling point, then:

Options

A. `DeltaH` is `-ve`, `DeltaS` is `+ve`
B. `DeltaH` and `DeltaS` both are `+ve`
C. `DeltaH` and `DeltaS` both are `-ve`
D. `DeltaH` is `+ve`, `DeltaS` is `-ve`

Answer

B

Explanation

For an endothermic reaction, `DeltaH=+ve`. Thus `DeltaH` is not favourable. As the reaction becomes spontaneous at higher temperature `DeltaS` has to be `+ve` (i.e., favourable).