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The enthalpy of formation of ammonia is ...

The enthalpy of formation of ammonia is `- 46.2 mol^(-1)`. The enthalpy change for the reaction
`2NH_(3) rarr N_(2) + 3 H_(2)` is

A

`42.0 kJ`

B

`64.0 kJ`

C

`80.0 kJ`

D

`92.0 kJ`

Text Solution

Verified by Experts

The correct Answer is:
D
`underset(2"moles")(2NH_(3))toN_(2)+3H_(2)`
The enthalpy of formation of ammonia
`=-46kJ mol^(-1)`
`DeltaH"of given reaction " =-2xx(-46)=92kJ`
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DINESH PUBLICATION-CHEMICAL THERMODYNAMICS AND CHEMICAL ENERGETICS -Exercise
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  16. The system in which there is no exchange of matter, work, or energy fr...

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