An ideal gas expands from `1xx10^(-3)m^(3)` to `1xx10^(-2)m^(3)` at `300K` againts a constant pressure of `1xx10^(5)Nm^(-2)` . The work done is :

Options

A. `-900 J`
B. `900 kJ`
C. `270 kJ`
D. `-900 kJ`

Answer

A

Explanation

`W=-PDeltaV`
`=-(1xx10^(5)Nm^(-2))(1xx10^(-2)-1xx10^(-3))m^(3)`
`=-(1xx10^(5)Nm^(-2))(1xx10^(-2)-0.1xx10^(-2))m^(3)`
`=-(1xx10^(5)Nm^(-2))(1-0.1)xx10^(-2)m^(3)`
`=-1xx10^(5)xx0.9xx10^(-2)Nm`
`=-0.9xx10^(3)Nm=-9xx10^(2)J=-900 J`