For a spontaneous reaction, `DeltaG,` equilibrium constant (K) and `E_(cell)^(@)` will be respectively:

Options

A. `-ve`, `gt 1`, `+ve`
B. `+ve`, `gt 1`, `-ve`
C. `-ve`, `lt 1`, `-ve`
D. `-ve`, `gt 1`, `-ve`

Answer

A

Explanation

For a spontaneous reaction `DeltaG` is `-ve`
`DeltaG=-RT ln K`
or `ln K` is `+ve implies K gt1`
Now `DeltaG=-nFE_("cell")`
As `DeltaG` is `-ve` for a spontaneous reaction. `E_("cell")` for such a reaction is `+ve`.