`0.06` mole of `KNO_(3)` is added to `100cm^(3)` of water at `298 K`. The enthalpy of `KNO_(3)(aq)` solution is `35.8 kJ mol^(-1)`. After the solute is dissolved, the temerature of the solution will be

Options

A. `293 K`
B. `298 K`
C. `301 K`
D. `304 K`

Answer

A

Explanation

Dissolution of `KNO_(3)` is endothermic
`DeltaH_(sol)=35.8 kJ mol^(-1)`
`:. "Heat absorbed when" 0.06 "mole of" KNO_(3) "is dissolved" =35.8xx0.06kJ=2148 J`
`q=mxxcxxDeltaT`
`:. 2148=100x4.184xxDeltaT` or `DeltaT=5K`
`:. ` Temperature of the solution `=298-5=293`