Enthalpy is equal to

Options

A. `T^(2)[(delta(G//T))/(deltaT)]_(P)`
B. `-T^(2)[(delta(G//T))/(deltaT)]_(P)`
C. `T^(2)[(delta(G//T))/(deltaT)]_(V)`
D. `-T^(2)[(delta(G//T))/(deltaT)]_(V)`

Answer

B

Explanation

It can be derived that `[(delta(G//T))/(deltaT)]_(P)=-(DeltaH)/(T^(2))`
or `DeltaH=-T^(2)[(delta(G//T))/(deltaT)]_(P)`
This is one of the forms of Gibbs-Hemholtz equation