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For a reaction A+2BtoC+D, if DeltaH=-25k...

For a reaction `A+2BtoC+D`, if `DeltaH=-25kcal`, `T=300 K` and `DeltaS=90 cal`, then the reaction is

A

reversible at `300 K`

B

irreversible at `300 K`

C

equilibrium, at `300 K`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaG=DeltaH-TDeltaS`
`=-25000 cal mol^(-1)-300 K(90 cal K^(-1)mol^(-1))`
`=-52000 cal mol^(-1)`
Since `DeltaG` is negative, process is spontaneous and hence irreversible thermodynamically.
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