The amount of heat evolved when `500 cm^(3) 0.1 M HCl` is mixed with `200 cm^(3)` of `0.2 M NaOH` is

Options

A. `2.292 kJ`
B. `1.292 kJ`
C. `0.292 kJ`
D. `5.292 kJ`

Answer

A

Explanation

`500cm^(3)` of `0.1 M HCl=0.05 mol`.
`200 cm^(3)` of `0.2 MNaOH=0.04 mol`
`0.04 mol` of `NaOH` neutralize `0.04 mol` of `HCl` and `0.04 mol` of `H_(2)O` is formed.
Heat evolved `=57.3xx0.04=2.292 kJ`