At the sublimation temperature, for the process `CO_(2)(S)toCO_(2)(g)`

Options

A. `DeltaH`, `DeltaS` and `DeltaG` will be negative
B. `DeltaH gt 0`, `DeltaS gt 0` and `DeltaG lt 0`
C. `DeltaH lt 0`, `DeltaS gt 0` and `DeltaG lt 0`
D. `DeltaH gt 0`, `DeltaS gt 0` and `DeltaG gt 0`

Answer

D

Explanation

Process being in equilibrium, `DeltaG=0`. It possible only when `DeltaH` and `TDeltaS` are equal and oppose each other. Thus, we should have either `DeltaH` and `DeltaS` both `+ve` or both `-ve`.