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One mole of non-ideal gas undergoes a ch...

One mole of non-ideal gas undergoes a change of state (`2.0 "atm"`, `3.0 L`, `95 K`) `to` (`4.0 "atm"`, `5.0 L`, `245 K`) with a change in internal energy, `DeltaU=30.0 L atm`. The change in enthalpy `(DeltaH)` of the process in `L "atm"` is

A

`40.0`

B

`42.3`

C

`44.0`

D

not defined because pressure is not constant

Text Solution

Verified by Experts

The correct Answer is:
C
`H=U+PV`
`DeltaH=DeltaU+DeltaPV`
`DeltaH=DeltaU+(P_(2)V_(2)-P_(1)V_(1))`
`=30+(5xx4-3xx2)`
`=30+(20-6)=44 L` atm
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DINESH PUBLICATION-CHEMICAL THERMODYNAMICS AND CHEMICAL ENERGETICS -Exercise
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