If the enthaply change for the transition of liquid water to steam is 30 KJ `"mol"^(-1)` at `27^(@)` C . The entropy change for the process would be

Options

A. `0.1 J mol^(-1) K^(-1)`
B. `100 J mol^(-1) K^(-1)`
C. `10 J mol^(-1) K^(-1)`
D. `1.0 J mol^(-1) K^(-1)`

Answer

B

Explanation

`"Liquid water" to"Steam"`
`DeltaG^(@)=DeltaH^(@)-TDeltaS^(@)`
`=30xx10^(3)-TDeltaS`
`:. DeltaS=(30xx10^(3))/(300)=100 J mol^(-1)K^(-1)`